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I need to evaporate 277.5 kg of water and 462.5 kg of p-xylene first, and then evaporate 112.5 kg of p-xylene. The total amount to be evaporated is...

2016-11-25View Original

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This post was last edited by raven2013 on 2016-11-25 09:07. Seeking help; it seems it was posted in the wrong section earlier. Let’s upload it again this time. I need to evaporate 277.5 kg of water and 462.5 kg of p-xylene first, and then 112.5 kg of p-xylene. Where should I start calculating the total amount to be evaporated? Are there calculation methods in the principles of chemical engineering or process design manuals? I forgot to add that water and xylene form an azeotrope
Reply #22016-11-25
Isn’t the total evaporation the sum of the three?
Reply #32016-11-25
Yeah. How do you calculate the individual evaporation amount?
Reply #42016-11-25
Q=cm△t c: specific heat capacity m: mass △t: temperature difference
Reply #52016-11-25
This post was last edited by raven2013 on 2016-11-25 09:38. Thank you. Does this temperature difference refer to the difference between the inlet and outlet temperatures? In: 102, Out: 40 – isn’t the temperature difference too large?

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