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280/1000 = (cubic meters per second squared / 22.4) * molecular weight of ammonia, which is 10. Is this calculation correct?
1. 280 KG of ammonia = 280*1000/17 mol = 16470.6 mol; 16470.6 mol * 22.4 L/mol = 368941 L.
2. 280 KG per hour of ammonia is approximately equal to 368941 L per hour, which is 368.9 m3 per hour
This post was last edited by bfdlwolf on 2019-6-19 at 16:39. “The density of ammonia under standard conditions is 0.771 Kg/m3, with a flow rate of 363.16 Nm3/h. Ammonia is not an ideal gas under standard conditions either.”
The original poster is unbeatable – the units aren’t clear, and the molecular weight is written randomly! Conversion factor for mass units to cubic meters: 280/17×22.4=368.94 Nm3/hr