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What is the flue gas volume for a 1.1 million-ton coking furnace? Please, expert!

2018-03-04View Original

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2x55 holes, with a hole diameter of 5.5m; the daily gas consumption is 32,000 cubic meters. Can the smoke volume be calculated based on this? Please provide the calculation method. Thank you????
Reply #22018-03-04
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Reply #32018-03-06
To calculate the flue gas volume accurately, it is necessary to know the composition of the gas and the air excess factor. As a rough estimate, 1 cubic meter of coke oven gas produces 6 cubic meters of flue gas.
Reply #42018-03-23
2x55 holes, with a hole diameter of 5.5m; is the daily gas consumption 32,000 cubic meters? ? Or per hour? Not at full capacity?
Reply #52018-04-03
The hourly flue gas volume, converted to standard conditions, is approximately 200,000–230,000 cubic meters
Reply #62018-08-10
Around 320,000; the fan selection should be based on a value of 350,000
Reply #72018-08-13
Based on the amount of gas consumed, (including wild wind), 1 cubic meter of gas generates 8 cubic meters of waste gas; this is the same calculation method used to determine the amount of waste gas for waste heat recovery power generation from flue gas
Reply #82018-08-23
Based on the composition of the gas and the chemical reaction equations with oxygen, the theoretical amount of oxygen (and air) required, as well as the amounts of products after combustion, are calculated. The composition of the gas is as follows: Content, Reaction Equation, Theoretical Oxygen Consumption. VCO2: 62.91; H2+0.5O2=H2O; 0.5; 31.46. CH4: 21.89; CH4+2O2=CO2+2H2O; 2; 43.78. CO: 5.51; CO+0.5O2=CO2; 0.5; 2.76. CnHm: 1.86×0.8; C2H4+3O2=2CO2+2H2O; 3; 4.46. Also, 1.86×0.2; C6H6+7.5O2=6CO2+3H2O; 7.5; 2.79. Products: CO2: 2.13; O2: 0.49; N2: 5.22; H2O: 2.35. Theoretical values for oxygen consumption and products are 84.76, 34.74, 113.14, and 5.22 respectively. The actual amount of air, along with the oxygen and nitrogen introduced, is calculated as follows: L_actual = α×L_theoretical = α×O_theoretical×(100/21). Thus, 1.3×84.76×(100/21) = 524.70. Then, 524.70×0.0235×0.6 = 7.40. Additionally, 524.70×0.79 = 414.51, and 524.70×0.21 – 84.76 = 25.43. The amounts of various components in the exhaust gas, in cubic meters, are 34.74, 120.54, 419.73, 25.43, totaling 600.44 cubic meters. The volume percentage of these components in the exhaust gas is 5.798%, 20.08%, 69.90%, 4.24%, adding up to 100.00%. Note: CnHm is calculated based on 80% C2H4 and 20% C6H6. The saturation temperature of the gas is 20°C, with a relative humidity of 0.6. The air excess factor α is set at 1.3. As a result, 100 cubic meters of gas, when completely burned, produce 600.44 cubic meters of exhaust gas, meaning that each cubic meter of gas generates 6 cubic meters of exhaust gas. So, whether it’s per day or per hour, just multiply your gas consumption by 6 to get the amount of waste gas you need.
Reply #92018-08-23
Theory is translated into practice; this calculation and approach are really excellent

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