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The high exhaust temperature of vertical oil-free reciprocating vacuum pumps is caused by gas compression; theoretically, the higher the exhaust pressure, the higher the temperature as well. Can it be understood in this way?
It also depends on whether it is compatible with the main pump and the intermediate pump
The higher the compression ratio, the greater the temperature rise.
For the same pump, with the exhaust pressure remaining essentially constant, the lower the intake pressure (the higher the vacuum level), the greater the compression ratio, right?
For the same pump, with the exhaust pressure remaining essentially constant, the lower the intake pressure (the higher the vacuum level), the greater the compression ratio, right? 1. For the same pump, if the inlet pressure varies, the outlet pressure will also vary ; 2. If the exhaust pressure is the same, the lower the intake pressure, the higher the compression ratio. Yes.
For the same vacuum pump, at first the pumping volume is high and the exhaust pressure is greater than the exhaust resistance; as the volume of air drawn in decreases, it gradually approaches the exhaust pressure, and eventually the pumping volume becomes very low. At that point, almost all of the work done by the pump is converted into heat, resulting in an increase in temperature. Is that how it can be understood?