Registered for the course on power and fundamental knowledge; have questions regarding the **exercises** after the lesson on pumps. Electric version
Thread Content
In Chapter 3, Exercise 72 asks: For a backward-curved centrifugal pump impeller with a rotational speed of n1=1750 RPM, an outlet installation angle of 60 degrees, an outlet diameter of D=150 mm, a thickness of b=15 mm, and a flow rate of 20 L/s, what is the theoretical head? In the answer, regarding the calculation of Vr2, which is the radial component of the actual exit flow velocity, it is stated that Q=Π*D*b*Vr2. I don’t understand how Π*D*b can represent the surface area of the exit diameter I hope the expert can provide an answer.
There seems to be a formula for the theoretical head; by plugging in the values, you can calculate it. As for this area, it is actually the surface area of the cylindrical surface at the outer edge of the impeller