Welding joint coefficient problem?
Thread Content
Certificate renewal questions 1. Based on the weld number of the vessel in the picture, try to determine the welding joint coefficient used in the calculation formula for the thickness of each pressure component (one or the smaller of φ1 to φ10) a) The joint coefficient used in the cylinder thickness calculation formula ( ) b) The joint coefficient used in the conical head calculation formula ( ) c) The joint coefficient used in the spherical head thickness calculation formula ( ) d) The joint coefficient used in the elliptical head thickness calculation formula ( )
This question is unreasonable. Very few people design it, using an elliptical head on the top and a spherical head on the bottom.
This is purely an exam question.
This question often comes up during exchanges, so please answer it actively.
cylinder: φ4 conical head: Big end φ5, small end φ6, φ7 small value elliptical head: φ1 φ2 small value ball head: φ8 φ9 φ10 Minimum value
Why is the elliptical head a small value of φ1 and φ2? Isn’t φ3 a Class A weld?
What does it mean to indicate two welding joint coefficients, namely φ1 and φ2, on a weld of an elliptical head?
φ3 is Class B weld (elliptical head)
φ1 ring weld φ2 circumferential interface weld
As a piece of equipment, the butt welds, weld forms and non-destructive testing ratios of cylinders, elliptical heads, cones and spherical heads should be the same. Just like circumferential seams bear less force than longitudinal seams, but the same non-destructive testing is still used. So φ1~φ10 are equal.