How to calculate the conversion of transmitter current and pressure to differential pressure

Hahahahaha. If none of this is taught, how can one survive the probation period?

Example 1: A pressure transmitter has an output signal of 4-20mA, with a range of 0-25MPa. What is the output current of the transmitter when the input pressure is 16MPa? Solution: The value of any signal from the instrument = Signal lower limit + (Signal upper limit – Signal lower limit) × … = 4 + (20 – 4) × = 14.24 (mA). Answer: When the input pressure to the pressure transmitter is 16 MPa, the output current of the transmitter is 14.24 mA. Example 2: In a certain temperature transmitter, there is a linear relationship between temperature and current; its output is in the range of 4–20 mA, corresponding to a temperature range of 0–200°C. What is the temperature when the transmitter outputs 16 mA? Solution: Using the following formula, the value of any measurement taken by the instrument is equal to the lower measurement limit plus (upper measurement limit – lower measurement limit) × %. Thus, it is 0 + (200 – 0) × %^2 = 150°C. Answer: When the temperature transmitter outputs 16 mA, the temperature is 150°C. Example 3: A pressure display instrument has an input signal of 1–5 V, with a range of -25 to 25 kPa. What should be the pressure reading when the input voltage is 2 V? Solution: Using the formula, the value read by the flow meter is equal to the lower measurement limit plus (upper measurement limit – lower measurement limit) × … = -25 + × = -12.5 kPa. Answer: When the input voltage is 2 V, the pressure reading should be -12.5 kPa. Example 4: A certain pressure transmitter has a measurement range of -1 to 5 bar, with an output current corresponding to a range of 0–10 V. What is the pressure when the output current is 6.62 V? Solution: Any measured value of the instrument = measurement lower limit + (measurement upper limit – measurement lower limit) × = -1 + × = 2.971 bar. Answer: When the output current is 6.62 V, the pressure should be 2.971 bar. Example 5: For a certain pneumatic flow meter, the differential pressure transmitter outputs a value of 20–100 kPa, corresponding to a range of 0–36 t/h. What is the output signal of the transmitter in kPa when the flow rate is 18 t/h? Solution: The value of any signal from the instrument = Signal lower limit + (Signal upper limit – Signal lower limit) × ^2 = 20 + (100 – 20) × ^2 = 40 kPa. Answer: When the flow rate is 18 t/h, the output signal of the transmitter is 40 kPa

Haha\ud83d\ude04, there’s nothing to do about it – you only realize you lack knowledge when you need it

I’ve learned it; I’ll save it. Thanks to the person above

×How should I understand the less-than sign, sir?

Do you mean this “X”? Multiplication. “^2” means square.

It depends on the specific instrument; generally, it involves a linear conversion based on a corresponding ratio, but some instruments require calculation after being activated